(B) The reducing power of a species is inversely proportional to its standard reduction potential $(E^o)$.The given standard reduction potentials are:

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(B) The reducing power of a species is inversely proportional to its standard reduction potential $(E^o)$.The given standard reduction potentials are:$E^o (Al^{3+}/Al) = -1.66 \ V$$E^o (Fe^{3+}/Fe^{2+}) = +0.77 \ V$$E^o (Br_2/Br^-) = +1.09 \ V$$A$ more negative $E^o$ value indicates a stronger reducing agent.Comparing the values: $-1.66 \ V Therefore,the order of reducing power is $Br^- < Fe^{2+} < Al$.

Class 12 Chemistry Electrochemistry Electrode potential and ECell

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Given:
$Fe^{3+}_{(aq)} + e^- \to Fe^{2+}_{(aq)}; E^o = +0.77 \ V$
$Al^{3+}_{(aq)} + 3e^- \to Al_{(s)}; E^o = -1.66 \ V$
$Br_{2(aq)} + 2e^- \to 2Br^-_{(aq)}; E^o = +1.09 \ V$
Considering the electrode potentials,which of the following represents the correct order of reducing power?

JEE MAIN 2014 All JEE MAIN

A
$Fe^{2+} < Al < Br^-$
B
$Br^- < Fe^{2+} < Al$
C
$Al < Br^- < Fe^{2+}$
D
$Br^- < Fe^{2+} < Al$

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Electrode potential and ECell

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Given:$Fe^{3+}_{(aq)} + e^- \to Fe^{2+}_{(aq)}; E^o = +0.77 \ V$$Al^{3+}_{(aq)} + 3e^- \to Al_{(s)}; E^o = -1.66 \ V$$Br_{2(aq)} + 2e^- \to 2Br^-_{(aq)}; E^o = +1.09 \ V$Considering the electrode potentials,which of the following represents the correct order of reducing power?

Similar Questions

Which of the following metals does not liberate $\text{H}_2$ gas by reacting with $\text{HCl}$?

The $E^{\ominus}$ for $Cl_{2}/Cl^{-}$ is $+1.36 \ V,$ for $I_{2}/I^{-}$ is $+0.53 \ V,$ for $Ag^{+}/Ag$ is $+0.79 \ V,$ $Na^{+}/Na$ is $-2.71 \ V$ and for $Li^{+}/Li$ is $-3.04 \ V.$ Arrange the following ionic species in decreasing order of reducing strength: $I^{-}, Ag, Cl^{-}, Li, Na$

The standard electrode potential for the half-cell reactions are$Zn^{2+} + 2e^{-} \longrightarrow Zn ; E^{\circ} = -0.76 \ V$$Fe^{2+} + 2e^{-} \longrightarrow Fe ; E^{\circ} = -0.44 \ V$The $emf$ of the cell reaction,$Fe^{2+} + Zn \longrightarrow Zn^{2+} + Fe$ is

What is the standard potential of the cell $Ni|Ni^{2+}_{(1 \ M)} || Cu^{2+}_{(1 \ M)}| Cu$ (in $V$)? Given $E^{\circ}_{Cu^{2+}/Cu} = 0.337 \ V$ and $E^{\circ}_{Ni^{2+}/Ni} = -0.236 \ V$.

What is standard electrode potential?

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Given:
$Fe^{3+}_{(aq)} + e^- \to Fe^{2+}_{(aq)}; E^o = +0.77 \ V$
$Al^{3+}_{(aq)} + 3e^- \to Al_{(s)}; E^o = -1.66 \ V$
$Br_{2(aq)} + 2e^- \to 2Br^-_{(aq)}; E^o = +1.09 \ V$
Considering the electrode potentials,which of the following represents the correct order of reducing power?

The standard electrode potential for the half-cell reactions are
$Zn^{2+} + 2e^{-} \longrightarrow Zn ; E^{\circ} = -0.76 \ V$
$Fe^{2+} + 2e^{-} \longrightarrow Fe ; E^{\circ} = -0.44 \ V$
The $emf$ of the cell reaction,
$Fe^{2+} + Zn \longrightarrow Zn^{2+} + Fe$ is